数学：一元二次方程化顶点式
问题描述：
数学：一元二次方程化顶点式
y=（x-10）[1000-30（x-10）]-5750
答
y=1000(x-10)-30(x-10)^2-5750
=-30[(x-10)^2-100/3(x-10)]-5730
=-30{[(x-10)-50/3]^2-2500/9}-5750
=-30(x-80/3)^2+75000/3-5750
=-30(x-80/3)^2+19250