(2x-y)/3 = (x+3y)/5 =2 求x、y

问题描述:

(2x-y)/3 = (x+3y)/5 =2 求x、y


(2x-y)/3=2
(x+3y)/5=2

2x-y=6 ①
x+3y=10 ②
①×3得:6x-3y=18 ③
③+②得:
7x=28
∴x=4,y=2