如图,△ABC的三个顶点都在○O上,AB为直径,CD平分∠ACB,∠CAB=30°,求AB AD和BD 的长

问题描述:

如图,△ABC的三个顶点都在○O上,AB为直径,CD平分∠ACB,∠CAB=30°,求AB AD和BD 的长

是不是这个三角形abc的三个顶点都在圆o上,ab为直径 ==> ∠C = 90°;==>RtΔCAB∠CAB = 30° ==> BC = 1/2 *AB;AC = √3/2 *AB ∴ AB = AC/(√3/2) = 2√3 ;BC =1/2 *AB = √3 CD平分角ACB ==> AD:BD = AC:BC = ...CD平分角ACB ==> AD:BD = AC:BC = 3:√3 --- (1)

怎么得到的??∵AB为直径∴∠ADB=∠ACB=90°
∴AD:BD = AC:BC = 3:√3
求采纳