已知df(x)=1/(9+2x+x^2)dx求f(x)
问题描述:
已知df(x)=1/(9+2x+x^2)dx求f(x)
答
df(x)/dx=1/(9+2x+x^2)f(x)=∫dx/(9+2x+x^2)=∫dx/(8+1+2x+x^2)=∫dx/[(x+1)^+8]=(1/8)∫dx/{[(x+1)/2√2]+1}令u=(x+1)/2√2,du=1/2√2dx=(2√2/8)∫du/(u^2+1)=(√2/4)arctanu+C=(√2/4)arctan[(x+1)/2√2]+C...