已知函数a>0,函数f(x)=-2asin(2x+π/6)+2a+b,当x∈[0,π/2]时,-5
问题描述:
已知函数a>0,函数f(x)=-2asin(2x+π/6)+2a+b,当x∈[0,π/2]时,-5设g(x)=f(x+π/2)且lg g(x)>0,求g(x)的单调区间.
答
当x∈[0,π/2]时,-1/2
已知函数a>0,函数f(x)=-2asin(2x+π/6)+2a+b,当x∈[0,π/2]时,-5设g(x)=f(x+π/2)且lg g(x)>0,求g(x)的单调区间.
当x∈[0,π/2]时,-1/2