已知函数f(x)=cos(2x-2π/3)-cos2x(x属于r) 求函数f(x)的最小正周期及单调递增区间

问题描述:

已知函数f(x)=cos(2x-2π/3)-cos2x(x属于r) 求函数f(x)的最小正周期及单调递增区间

f(x)=cos(2x-2π/3)-cos2x=-2sin(2x-π/3)sin(-2π/3)=√3sin(2x-π/3)
最小正周期π,单调递增区间2kπ-π/2