简便运算:8+2001×(1/8−1/2009)+8×(1/2001−1/2009)−2009×(1/8+1/2001).

问题描述:

简便运算:8+2001×(

1
8
1
2009
)+8×(
1
2001
1
2009
−2009×(
1
8
+
1
2001
)

8+2001×(

1
8
-
1
2009
)+8×(
1
2001
-
1
2009
)-2009×(
1
8
+
1
2001

=8+
2001
8
-
2001
2009
+
8
2001
-
8
2009
-
2009
8
-
2009
2001

=8+(
2001
8
-
2009
8
)-(
2001
2009
+
8
2009
)-(
2009
2001
-
8
2001

=8-1-1-1
=5