9倍根号1/54除以3/2倍根号3/5乘以1/2倍根号2又2/3
问题描述：
9倍根号1/54除以3/2倍根号3/5乘以1/2倍根号2又2/3
答
原式={√(81×1/54)/√(9/4×3/5)]}*√(1/4×8/3)
={√(3/2)/[3/2√(3/5)]}*√(2/3)
=√(3/2)*√(2/3)/[3/2√(3/5)]
=1/(3√15/10)
=10/(3√15)
=2√15/9