(sin^2α+sin2α)/(cos^2α+cos2α)化简

问题描述:

(sin^2α+sin2α)/(cos^2α+cos2α)化简

(sin^2a+sin2a)/(cosa^2+cos2a)
=(sin^2a+2sina*cosaa)/(2cos^2a-sin^2a)
上下都除以cosx^2,
得(tan^2a+2tana)/(2-tan^2a)