已知25a2-10a+1+|4b+1|=0,求[(4a+3b)(4a-3b)-(2a-5b)(8a+5b)]÷(-2b).
问题描述:
已知25a2-10a+1+|4b+1|=0,求[(4a+3b)(4a-3b)-(2a-5b)(8a+5b)]÷(-2b).
答
∵25a2-10a+1+|4b+1|=0,∴(5a-1)2+|4b+1|=0,
∴a=
、b=−1 5
1 4
∴[(4a+3b)(4a-3b)-(2a-5b)(8a+5b)]÷(-2b)
=(16a2-9b2-16a2+25b2+30ab)÷(-2b)
=(16b2+30ab)÷(-2b)
=-8b-15a
=-8×(-
)-15×1 4
1 5
=2-3
=-1.