-m²n(x-y)n次方+mn²(x-y)n-1次方
问题描述：
-m²n(x-y)n次方+mn²(x-y)n-1次方
答
-m²n(x-y)n次方+mn²(x-y)n-1次方 提取公因式-mn(x-y)n-1次方
=-mn(x-y)n-1次方×[m(x-y)-n]
=-mn(x-y)n-1次方×(mx-my-n)
答
-m²n(x-y)^n+mn²(x-y)^(n-1)
mn[n(x-y)^(n-1)-m(x-y)^n]
=mn(x-y)^(n-1)[n-m(x-y)]
=mn(my-mx+n)(x-y)^(n-1)