设x1=1,x2=2,xn+2=根号下xn+1*xn 求limn→∞ xn
问题描述：
设x1=1,x2=2,xn+2=根号下xn+1*xn 求limn→∞ xn
答
xn+2=根号下xn+1*xn 你可以解释一下吗?xn是个数列，xn+2=根号下（xn+1乘xn)
设x1=1,x2=2,xn+2=根号下xn+1*xn 求limn→∞ xn
xn+2=根号下xn+1*xn 你可以解释一下吗?xn是个数列，xn+2=根号下（xn+1乘xn)