x^+2x=0 x^-25=0 x^+5x-1=0 (x+1)^2=2x(x-1)^2
问题描述:
x^+2x=0 x^-25=0 x^+5x-1=0 (x+1)^2=2x(x-1)^2
答
x^+2x=0
x(x+2)=0
x=0,x=-2
x^-25=0
(x+5)(x-5)=0
x=-5,x=5
x^+5x-1=0
x=(-5±√29)/2
(x+1)^2=2(x-1)^2
x²+2x+1=2x²-4x+2
x²-6x+1=0
x=3±2√2