化简(x的平方-4/x的平方-4x+4+2-x/x+2)/x/x-2,其结果是

问题描述:

化简(x的平方-4/x的平方-4x+4+2-x/x+2)/x/x-2,其结果是

=((x+2)(x-2)/(x-2)^2+2-x/x+2)/x/x-2
=((x+2)/(x-2)-(x-2)/(x+2))/x/x-2
=(((x+2)^2-(x-2)^2)/(x-2)(x+2))/x/x-2
=((x^2+4x+4-x^2+4x-4))/(x-2)(x+2))/x/x-2
=8/(x+2)