已知tanx=2,求4sinx-2cosx/3cosx+3sinx值?
问题描述:
已知tanx=2,求4sinx-2cosx/3cosx+3sinx值?
答
4sinx-2cosx/3cosx+3sinx
=[(4sinx-2cosx)/cosx]/[(3cosx+3sinx)/cosx]
=(4tanx-2)/(3tanx+3)
=(4*2-2)/(3*2+3)
=2/3