sin(540-α)/tan(α-180)*cot(-α-360)/tan(900-α)*cos(720-α)/sin(-α-360)
问题描述:
sin(540-α)/tan(α-180)*cot(-α-360)/tan(900-α)*cos(720-α)/sin(-α-360)
答
原式=sin(180º-α)/tan(180º+α)]·cot(-α)]/tan(180º-α)·cos(-α)/sin(-α)
=sinα/tanα·(-cotα)/(-tanα)·cosα/(-sinα)
=sinα·(cosα/sinα)·cot²α·(-cotα)
=-cosα·cot³α