已知方程3/5+2(x+1/2011)=1/5,求代数式10-20(x+1/2011)的值.

问题描述:

已知方程3/5+2(x+1/2011)=1/5,求代数式10-20(x+1/2011)的值.

3/5+2(x+1/2011)=1/5
2(x+1/2011)=-2/5
-20(x+1/2011)=(-2/5)*(-10)=4
10-20(x+1/2011)=10+4=14