已知函数f(x)= {log2x,x>0,f(x+3)x≤0} 则f(-10)的值是

问题描述:

已知函数f(x)= {log2x,x>0,f(x+3)x≤0} 则f(-10)的值是

-10f(-10)
=f(-10+3)
=f(-7)
同理
=f(-4)
=f(-1)
=f(2)
=log2(2)
=1