化简;[x+3/x+2]+[2-x/x平方-4]的值

问题描述:

化简;[x+3/x+2]+[2-x/x平方-4]的值

原式=(x+3)/(x+2)-(x-2)/(x+2)(x-2)
=(x+3)/(x+2)-1/(x+2)
=(x+3-1)/(x+2)
=(x+2)/(x+2)
=1