已知函数fx=Asin(wx+φ)(A>0,w>0,0
问题描述:
已知函数fx=Asin(wx+φ)(A>0,w>0,0
答
解析:因为f(x)=Asin(wx+φ)(A>0,w>0,0w=2
所以,f(x)=2sin(2x+φ)==>f(π/12)=2sin(π/6+φ)=2==>φ=π/3
所以,f(x)=2sin(2x+π/3)
单调减区间:2kπ+π/2