解二元一次方程组:x/3+y/7=7,x/2-y/3=-1
问题描述:
解二元一次方程组:x/3+y/7=7,x/2-y/3=-1
答
x/3+y/7=7 (1)
x/2-y/3=-1 (2)
(1)×7+(2)×3
7x/3+3x/2=49-3
23x/6=46
x=12
y=7(7-x/3)=21