已知2x-y/x+3y=2,求代数式4x-2y/x+3y减4x+12y除以2x-y
问题描述:
已知2x-y/x+3y=2,求代数式4x-2y/x+3y减4x+12y除以2x-y
答
2x-y/x+3y=2得
x+3y/2x-y=1/2
4x-2y/x+3y减4x+12y除以2x-y
=2(2x-y)/x+3y-4(x+3y)/2x-y
=2乘以2-4乖以1/2
=4-2
=2