设i为虚数单位,则复数i/2+i等于

问题描述:

设i为虚数单位,则复数i/2+i等于

i/(2+i)
=i(2-i)/[(2+i)(2-i)]
=(2i+1)/(4+1)
=(2i+1)/5

3/2i
3/2i 3/2i 3/2i

i/2+i=(1/2+1)i=3/2i
i/(2+i)
=i(2-i)/[(2+i)(2-i)]
=(2i+1)/(4+1)
=(2i+1)/5