(y+1)²-6（y+1)=-8 用因式分解来解
问题描述：
(y+1)²-6（y+1)=-8 用因式分解来解
答
(y+1)^2-6(y+1)+8=0
(y+1-2)(y+1-4)=0
(y-1)(y-3)=0
所以y-1=0或y-3=0
所以y=1或y=3
答
(y+1)²-6（y+1)=-8
（y+1)²-6(y+1)+8=0
(y+1-4)(y+1-2)=0
(y-3)(y-1)=0
y1=3, y2=1
答
(y+1)²-6（y+1)=-8 化为
(y+1)²-6（y+1)+8 =0
即(y+1-2)(y+1-4)=0
∴(y-1)(y-3)=0
∴y1=1,y2=3