解方程9（x²-1）²-4（x²+1）²=0
问题描述：
解方程9（x²-1）²-4（x²+1）²=0
答
9（x²-1）²-4（x²+1）²=0
[3(x²-1)-2(x²+1)][3(x²-1)+2(x²+1)]=0
[3x²-3-2x²-2][3x²-3+2x²+2]=0
[x²-5][5x²-1]=0
(x-√5)(x+√5)(x√5-1)(x√5+1)=0
x=√5或x=-√5或x=√5/5或x=-√5/5
答
9（x²-1）²-4（x²+1）²=0【3（x²-1）-2（x²+1）】【3（x²-1）+2（x²+1）】=0（x²-5）（5x²-1）=0x²-5=0,5x²-1=0x1=√5,x2=-√5,x3=√5/5,z4=-√5/5...