x+2y+z=0 x-y+2z=2 2x-y+3z=-1
问题描述:
x+2y+z=0 x-y+2z=2 2x-y+3z=-1
答
x+2y+z=0 …………(1)
x-y+2z=2 …………(2)
2x-y+3z=-1…………(3)
(1)+(2):2x+y+3z=2 …………(4)
(4)-(3) :2y=3 所以y=3/2=1.5
(1)-(2):3y-z=-2 即z=3y+2=3*1.5+2=6.5
再把y=1.5、z=6.5代入原方程组中任何一式,得x=-9.5
所以x=-9.5 y=1.5 z=6.5
答
1式加2式得 4式2x+y+3z=2
3式减4式得 2y=3 所以y=3/2
代入1式2式得 x+z=-3
x+2z=7/2所以x=-19/2
z=13/2
答
x+2y+z=0 x-y+2z=2 2x-y+3z=-1x+2y+z=0 ①x-y+2z=2 ②2x-y+3z=-1 ③①-②得 3y-z=-2 ④2*①-③得 5y-z=1 ⑤5*④-3*⑤得 -2z=-13, z=13/2代入z到④,得y=3/2代入y和z到①,得x=-19/2因此 x=-19/2 ...
答
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