解方程:1/x(x+1)+1/(x+1)(x+2)+1/(x+2)(x+3)+...+1/(x+9)(x+10)=5/12 急

1/x(x+1)+1/(x+1)(x+2)+1/(x+2)(x+3)+...+1/(x+9)(x+10)
=1/x-1/(x+1)+1/(x+1)-1/(x+2)+...+1/(x+9)-1/(x+10)
=1/x-1/(x+10)
=9/x(x+10)
=5/12
则5x（x+10）=108
所以：5x^2+50x-108=0
解得：

1/x-1/(x+1)+1/(x+1)-1/(x+2)+...+1/(x+8)-1/(x+9)+1/(x+9)-1/(x+10)=5/12
1/x-1/(x+10)=5/12
x+10-x=5/12·x(x-10)
x1=2,x2=-12

1/x(x+1)+1/(x+1)(x+2)+1/(x+2)(x+3)+...+1/(x+9)(x+10)=5/121/x-1/(x+1)+1/(x+1)-1/(x+2)+1/(x+2)-1/(x+3)+...+1/(x+9)-1/(x+10)=5/121/x-1/(x+10)=5/1210/x(x+10)=5/12所以x²+10x-24=0(x+12)(x-2)=0x=-12,x=2...

1/x(x+1)+1/(x+1)(x+2)+1/(x+2)(x+3)+...+1/(x+9)(x+10)=5/12
1/x-1/(x+1)+1/(x+1)-1/(x+2)+1/(x+2)-1/(x+3)+...+1/(x+9)-1/(x+10)=5/12
1/x-1/(x+10)=5/12
(x+10-x)/x(x+10)=5/12
x(x+10)=24
x=2或x=-12