2^-1*64^2/3-3^log的底数3(8)+log的底数5(4)*log的底数根号2(5)+(1/cos1)^0
问题描述：
2^-1*64^2/3-3^log的底数3(8)+log的底数5(4)*log的底数根号2(5)+(1/cos1)^0
答
=1/2*4^2-8+lg4/lg5*lg5/lg（2）^1/2+1=8-8+2lg2/lg5*lg5/（1/2*lg2）+1=4+1=5
答
原式=1/2x16-8+2lg2/lg5xlg5/(1/2)lg2+1
=5
答
2^-1*64^2/3-3^log的底数3(8)+log的底数5(4)*log的底数根号2(5)+(1/cos1)^0
=(1/2)*4^2- 8+2lg2/lg5* lg5/(1/2lg2) +1
=8-8+4+1
=5