分解因式：（xy-1）的平方+（x+y-2）（x+y-2xy）.

分类: 作业答案 • 2021-12-19 15:02:00

问题描述：

答

x+y-2xy)(x+y-2)
=(xy-1)^2+4xy+(x+y)^2-2(xy+1)(x+y)
=(xy+1)^2+(x+y)^

答

(xy-1)^2+(x+y-2xy)(x+y-2)
=(xy-1)^2+4xy+(x+y)^2-2(xy+1)(x+y)
=(xy+1)^2+(x+y)^2-2(xy+1)(x+y)
=(x+1)^2(y+1)^2