已知4sinx^2-cosx^2-6sinx+3cosx=0,求(cos2x-cosx^2)/(1-cotx^2)的值
问题描述：
已知4sinx^2-cosx^2-6sinx+3cosx=0,求(cos2x-cosx^2)/(1-cotx^2)的值
答
采取计算机求解.
4sinx^2-cosx^2-6sinx+3cosx=0
解得:x=0.42314452712305966176816614995526 (rad)
(cos2x-cosx^2)/(1-cotx^2)
解得:0.0710