求隐函数y的导数:xy-sin(πy∧2)=0要过程,谢谢
问题描述:
求隐函数y的导数:xy-sin(πy∧2)=0要过程,谢谢
答
y+xy'-cos(pi*y^2)*2piyy'=0
y'=y/[cos(pi*y^2)*2piy-x]