求隐函数y的导数:xy-sin(πy∧2)=0要过程,谢谢

问题描述:

求隐函数y的导数:xy-sin(πy∧2)=0要过程,谢谢

y+xy'-cos(pi*y^2)*2piyy'=0
y'=y/[cos(pi*y^2)*2piy-x]