数学因式分解计算题[(-x+y)/ (x²-y²)] - [(-x-y)/ (x+y)²]
问题描述:
数学因式分解计算题
[(-x+y)/ (x²-y²)] - [(-x-y)/ (x+y)²]
答
等于0
答
[(-x+y)/ (x²-y²)] - [(-x-y)/ (x+y)²]
=[-(x-y)/ (x+y)(x-y)] - [-(x+y)/ (x+y)²]
=[-1/ (x+y)] + [1/ (x+y)]
0