3/2cos2x+√3/2sin2x=√3sin(2x+π/3)这一步是怎么变的?

问题描述:

3/2cos2x+√3/2sin2x=√3sin(2x+π/3)这一步是怎么变的?

√3/2 +√3/2cos2x-1/2sin2x
=√3/2 +sin2π/3cos2x-cos2π/3sin2x
=√3/2 +罪(2π/3-2x)∴最大值为=√3/2 +1你这是啥啊 看清楚问题被