(x²+y²）-x²y²3ax²-3ay四次方p四次方-1
问题描述：
(x²+y²）-x²y²
3ax²-3ay四次方
p四次方-1
答
解(x²+y²）-x²y²
=（x^2+y^2+xy）（x^2+y^2-xy）
解3ax²-3ay^4
=3a(x^2-y^4)
=3a(x+y^2)(x-y^2)
解p^4-1
=(p^2+1)(p^2-1)
=(p^2+1)(p+1)(p-1)
答
(x²+y²）-x²y²
=（x²+y²+xy）（x²+y²-xy）
3ax²-3ay^4
=3a(x²-y^4)
=3a(x+y²)(x-y²)
p^4-1
=(p²+1)(p²-1)
=(p²+1)(p+1)(p-1)
就这样把，我已经用了最少的步骤了
答
(x²+y²）-x²y²
=（x^2+y^2+xy）（x^2+y^2-xy）
3ax²-3ay^4
=3a(x^2-y^4)
=3a(x+y^2)(x-y^2)
p^4-1
=(p^2+1)(p^2-1)
=(p^2+1)(p+1)(p-1)