若Ix+3I与I2y-3I互为相反数,求(x+y)除以(x-y)的直

问题描述:

若Ix+3I与I2y-3I互为相反数,求(x+y)除以(x-y)的直

因为|x+3|=-|2y-3|所以x-3=2y-3=0
x=3,y=1.5
(x+y)/(x-y)=3

x=-3
y=3/2
所以答案为1/3

因为|x+3|与|2y-3|互为相反数,所以|x+3|+|2y-3|=0,
因为|x+3|>=0,|2y-3|>=0,所以|x+3|=0,|2y-3|=0,
即x=-3,y=1.5,所以(x+y)/(x-y)=1/3

Ix+3I+I2y-3I=0
x=-3,y=3/2
(x+y)除以(x-y)=1/3

若|x+3|与|2y-3|互为相反数,则|x+3|+|2y-3|=0
因为|x+3|大于等于零,|2y-3|大于等于零
所以x+3=0 2y-3=0 x=-3 y=3/2 (x+y)/(x-y)=-3/2 除以 -9/2 =1/3
答:代数式的值为1/3.

互为相反数的两个数相加等于0
|x+3|+|2y-3|=0
因为|x+3|≥0,|2y-3|≥0
所以x+3=0,2y-3=0
求得,x=-3,y=1.5
(x+y)/(x-y)=(-3+1.5)/(-3-1.5)=(-1.5)/(-4.5)=1/3(答案是3分之1,/表示分数线)

Ix+3I+I2y-3I=0 x=-3,y=3/2 (x+y)除以(x-y)=1/3 互为相反数的两个数相加等于0 |x+3|+|2y-3|=0 因为|x+3|≥0,|2y-3|≥0 所以x+3=0,2y-3=0 求得,x=-3,y=1.5 (x+y)/(x-y)=(-3+1.5)/(-3-1.5)=(-1.5)/(-4.5)=1/3(答案是3...

由于带绝对值号,所以能成为相反数的只能为0
所以x=-3;y=3/2
x+y=-3/2
x-y=-9/2
(x+y)除以(x-y)=1/3