1/8{1/6[1/4(x-1/2+3)+5]+7}=1

问题描述:

1/8{1/6[1/4(x-1/2+3)+5]+7}=1

1/8{1/4[1/4(x-1/2+3)+5]+7}=1 1/8[1/4(x-1/2+3)+5]+7=8 1/8[1/4(x-1/2+3)+5]=1 1/4(x-1/2+3)+5=8 1/4(x-1/2+3)=3 (x-1)/2+3=12 (x-1)/2=9 x-1=18 x=19