x²-ax+a-1=0如何因式分解
问题描述：
x²-ax+a-1=0如何因式分解
答
x²-ax+a-1=x²-1-a(x-1)=(x+1)(x-1)-a(x-1)=(x-1)(x-a+1)
答
(x-1)[x-(a-1)]
答
妈啊，这什么玩意啊？能分
解的吗?
答
x^2-ax+a-1=0
(x-1)[x-(a-1)]=0
x1=1,x2=a-1
答
(x²-1)-ax+a=0
(x+1)(a-1)-a(x-1)=0
(x-1)(x+1-a)=0
x=1,x=a-1
答
x -(a-1)
x -1
[x-(a-1)](x-1)=0
答
x²-ax+a-1=0
x^2-[(a-1)+1]x+1*(a-1)=0
[x-(a-1)](x-1)=0
(x-a+1)(x-1)=0