函数y=2sin(x+π/3),x属于[π/6,π/2]的值域
问题描述:
函数y=2sin(x+π/3),x属于[π/6,π/2]的值域
答
π/6≤x≤π/2
π/2≤x+π/3≤5π/6
1/2≤sin(x+π/3)≤1≤
1≤2sin(x+π/3)≤2
答
先画y=sinX的图像,再横坐标不变,纵坐标变为原来的2倍,再向左平移π/3个单位,然后找x属于[π/6,π/2]的值域
答
π/6π/21/21所以函数值域为[1,2]