已知涵数f(x)=Asin(3x+y)(A>0),x属于负无穷到正无穷,0

问题描述:

已知涵数f(x)=Asin(3x+y)(A>0),x属于负无穷到正无穷,0

(1)最小正周期:T=2π/ω=2π/3(2)当x=π/12,f(X)max =4所以A=4,3*π/12+y=π/2,即y=π/4所以 f(x) = 4sin(3x+π/4)(3) 将x=2/3a+π/12代入f(x) 得 f(x)=4sin(2a+π/2)=12/5即sin(2a+π/2)=3/5 ,cos(2a)...