化简；[x+3/x+2]+[2-x/x平方-4]的值
问题描述：
化简；[x+3/x+2]+[2-x/x平方-4]的值
答
X^2-4=(X-2)(X+2)
所以(2-X)/(X^2-2)=-1/（X+2）
[(X+3)/(X+2)]-[1/(X+2)]=(X+2)/(X+2)=1
答
1
答
原式=(x+3)/(x+2)-(x-2)/(x+2)(x-2)
=(x+3)/(x+2)-1/(x+2)
=(x+3-1)/(x+2)
=(x+2)/(x+2)
=1
答
解答;
[(x+3)/(x+2)]+[(2-x)/(x平方-4)]=[(x+3)/(x+2)]-(x-2)/[(x+2)(x-2)
=(x+3)/(x+2)-1/(x+2)=(x+3-1)/(x=2）=（x=2)/(x+2)=1