y=arcsin(x-1/2) 求这个函数的定义域
问题描述:
y=arcsin(x-1/2) 求这个函数的定义域
答
-1<=x-1/2<=1,-1/2<=3/2
答
-1=
y=arcsin(x-1/2) 求这个函数的定义域
-1<=x-1/2<=1,-1/2<=3/2
-1=