2/1+4/1+8/1+16/1+32/1+64/1+128/1=?

是不是
1/2+1/4+1/8+1/16+1/32+1/64+1/128
=1/2+1/4+1/8+1/16+1/32+1/64+(1/128+1/128)-1/128
=1/2+1/4+1/8+1/16+1/32+(1/64+1/64)-1/128
=1/2+1/4+1/8+1/16+(1/32+1/32)-1/128
=1/2+1/4+1/8+(1/16+1/16)-1/128
=1/2+1/4+(1/8+1/8)-1/128
=1/2+(1/4+1/4)-1/128
=1/2+1/2-1/128
=1-1/128
=127/128

254

2分之1一般表示为1/2,而不是2/1 1/2+1/4+1/8+1/16+1/32+1/64+1/128 =1/2+1/4+1/8+1/16+1/32+1/64+(1/128+1/128)-1/128 =1/2+1/4+1/8+1/16+1/32+(1/64+1/64)-1/128 =1/2+1/4+1/8+1/16+(1/32+1/32)-1/128 =1/2+1/4+1/8...

2/1+4/1+8/1+16/1+32/1+64/1+128/1
=2+4+8+16+32+64+128
=254
是不是1/2+1/4+1/8+1/16+1/32+1/64+1/128
=1/2+1/4+1/8+1/16+1/32+1/64+1/128+1/128-1/128
=1/2+1/4+1/8+1/16+1/32+1/64+1/64-1/128
=1/2+1/4+1/8+1/16+1/32+1/32-1/128
=1/2+1/4+1/8+1/16+1/16-1/128
=1/2+1/4+1/8+1/8-1/128
=1/2+1/4+1/4-1/128
=1/2+1/2-1/128
=1-1/128
=127/128