2x-1-3(y-2)=x 2(x-1)-y=4y-18,
问题描述：
2x-1-3(y-2)=x 2(x-1)-y=4y-18,
答
2x-1-3(y-2)=x
2(x-1)-y=4y-18
x-3y=-5......(1)
2x-5y=-20......(2)
(1)*2-(2):
-y=10
y=-10
代回（1）:
x=3y-5=-35
答
2x-1-3(y-2)=x,则x=3y-5①
2(x-1)-y=4y-18,则2x-5y=-16②
①代入②,得2(3y-5)-5y=-16,解得y=-6
代入①,解得x=-23
所以x=-23,y=-6