1/（x-8）+1/(x-2)-1/(x-6)-1/(x-4)=0
问题描述：
1/（x-8）+1/(x-2)-1/(x-6)-1/(x-4)=0
答
1/（x-8）+1/(x-2)-1/(x-6)-1/(x-4)=0 1/（x-8）+1/(x-2)=1/(x-6)+1/(x-4) (x-2+x-8)/[(x-2)(x-8)]=(x-4+x-6)/[(x-4)(x-6) (2x-10)/(x^2-10x+16)=(2x-10)/(x^2-10x+24) (2x-10)(1/(x^2-10x+16)-16)-1/(x^2-10x+24))=...