6cos(2kπ+π/3)-2sin(2kπ+π/6)+3tan(2kπ) k€Z

问题描述:

6cos(2kπ+π/3)-2sin(2kπ+π/6)+3tan(2kπ) k€Z

3-1+0=2
cos(2kπ+π/3)=0.5
sin(2kπ+π/6)=0.5
tan(2kπ)=0

6cos(2kπ+π/3)-2sin(2kπ+π/6)+3tan(2kπ) k€Z
=6cos(π/3)-2sin(π/6)+3tan(0)
=3-1+0=2