解下列分式方程:(1)X/(X-2)+(X-9)/(X-7)=(X+1)/(X-1)+(X-8)/(X-6)

问题描述:

解下列分式方程:(1)X/(X-2)+(X-9)/(X-7)=(X+1)/(X-1)+(X-8)/(X-6)
还有几道 (2)(X+2)/(X+1)-(X+4)/(X+3)=(X+6)/(X+5)-(X+8)/(X+7) 解关于X的方程(2a)/(x-1)=2-a
过程讲仔细点啊!

(1)通分得
x^2-7x+x^2-11x+18=x^2-5x-6+x^2-9x+8
解得 x=4;
(2)左右分别通分得2/[(x+1)(x+3)]=2/[(x+5)(x+7)],
则分母相等且不为零,解得 x=-4;
(3)x=(2+a)/(2-a),a不等于2.