x²-6x+11=2,求x^100-3^99+X^99……x²-3x+1的值
问题描述:
x²-6x+11=2,求x^100-3^99+X^99……x²-3x+1的值
答
由x²-6x+11=2可得x²-6x+9=0,所以X=3
x^100-3^99+X^99……x²-3x+1
=3^100-3^99+3^99-3^98+……-3^2+3^2-3*3+1
=3^100-9+1
=3^100-8