(a+1)(a的平方-2a+3)
问题描述：
(a+1)(a的平方-2a+3)
答
答：
(a+1)(a²-2a+3)
=(a+1)[(a-1)²+2]
=(a+1)(a-1)²+2(a+1)
=(a²-1)(a-1)+2(a+1)
=a³-a²-a+1+2a+2
=a³-a²+a+3
答
：(a+1)(a的平方-2a+3)
=a³-2a²+3a+a的平方-2a+3
=a³-a²+a+3