因式分解：2x4-x3-6x2-x+2
问题描述：
因式分解：2x4-x3-6x2-x+2
答
2x4-x3-6x2-x+2 =x^2(2x^2-x-6)-(x-2)=x^2(2x+3)(x-2)-(x-2)=(x-2)[x^2(2x+3)-1]=(x-2)(2x^3+3x^2-1)=(x-2)[(2x^3+2x^2)+(x^2-1)]=(x-2)[2x^2(x+1)+(x+1)(x-1)]=(x-2)(x+1)(2x^2+x-1)=(x-2)(x+1)(2x-1)(x+1)=(x+1)^2...