3(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)-2^64=

问题描述:

3(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)-2^64=

3(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)-2^64
=(2^2-1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)-2^64
=(2^4-1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)-2^64
=(2^8-1)(2^8+1)(2^16+1)(2^32+1)-2^64
=(2^16-1)(2^16+1)(2^32+1)-2^64
=(2^32-1)(2^32+1)-2^64
=2^64-1-2^64
=-1